mirror of
https://github.com/erkin/ponysay.git
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3aded082c2
Signed-off-by: Mattias Andrée <maandree@operamail.com>
263 lines
9.9 KiB
Python
Executable file
263 lines
9.9 KiB
Python
Executable file
#!/usr/bin/env python3
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# -*- coding: utf-8 -*-
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'''
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ponysay - Ponysay, cowsay reimplementation for ponies
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Copyright (C) 2012, 2013 Erkin Batu Altunbaş et al.
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This program is free software: you can redistribute it and/or modify
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it under the terms of the GNU General Public License as published by
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the Free Software Foundation, either version 3 of the License, or
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(at your option) any later version.
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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GNU General Public License for more details.
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You should have received a copy of the GNU General Public License
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along with this program. If not, see <http://www.gnu.org/licenses/>.
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If you intend to redistribute ponysay or a fork of it commercially,
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it contains aggregated images, some of which may not be commercially
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redistribute, you would be required to remove those. To determine
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whether or not you may commercially redistribute an image make use
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that line ‘FREE: yes’, is included inside the image between two ‘$$$’
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lines and the ‘FREE’ is and upper case and directly followed by
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the colon.
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'''
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from common import *
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'''
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Class used for correcting spellos and typos,
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Note that this implementation will not find that correctly spelled word are correct faster than it corrects words.
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It is also limited to words of size 0 to 127 (inclusive)
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'''
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class SpelloCorrecter(): # Naïvely and quickly ported and adapted from optimised Java, may not be the nicest, or even fast, Python code
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'''
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Constructor
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@param directories:list<str> List of directories that contains the file names with the correct spelling
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@param ending:str The file name ending of the correctly spelled file names, this is removed for the name
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-- OR -- (emulated overloading [overloading is absent in Python])
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@param directories:list<str> The file names with the correct spelling
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'''
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def __init__(self, directories, ending = None):
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self.weights = {'k' : {'c' : 0.25, 'g' : 0.75, 'q' : 0.125},
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'c' : {'k' : 0.25, 'g' : 0.75, 's' : 0.5, 'z' : 0.5, 'q' : 0.125},
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's' : {'z' : 0.25, 'c' : 0.5},
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'z' : {'s' : 0.25, 'c' : 0.5},
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'g' : {'k' : 0.75, 'c' : 0.75, 'q' : 0.9},
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'o' : {'u' : 0.5},
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'u' : {'o' : 0.5, 'v' : 0.75, 'w' : 0.5},
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'b' : {'v' : 0.75},
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'v' : {'b' : 0.75, 'w' : 0.5, 'u' : 0.7},
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'w' : {'v' : 0.5, 'u' : 0.5},
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'q' : {'c' : 0.125, 'k' : 0.125, 'g' : 0.9}}
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self.corrections = None
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self.dictionary = [None] * 513
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self.reusable = [0] * 512
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self.dictionaryEnd = 512
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self.closestDistance = 0
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self.M = [None] * 128
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for y in range(0, 128):
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self.M[y] = [0] * 128
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self.M[y][0] = y
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m0 = self.M[0]
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x = 127
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while x > -1:
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m0[x] = x
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x -= 1
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previous = ''
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self.dictionary[-1] = previous;
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if ending is not None:
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for directory in directories:
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files = os.listdir(directory)
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files.sort()
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for filename in files:
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if (not endswith(filename, ending)) or (len(filename) - len(ending) > 127):
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continue
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proper = filename[:-len(ending)]
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if self.dictionaryEnd == 0:
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self.dictionaryEnd = len(self.dictionary)
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self.reusable = [0] * self.dictionaryEnd + self.reusable
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self.dictionary = [None] * self.dictionaryEnd + self.dictionary
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self.dictionaryEnd -= 1
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self.dictionary[self.dictionaryEnd] = proper
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prevCommon = min(len(previous), len(proper))
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for i in range(0, prevCommon):
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if previous[i] != proper[i]:
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prevCommon = i
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break
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previous = proper
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self.reusable[self.dictionaryEnd] = prevCommon
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else:
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files = directories
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files.sort()
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for proper in files:
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if len(proper) > 127:
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continue
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if self.dictionaryEnd == 0:
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self.dictionaryEnd = len(self.dictionary)
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self.reusable = [0] * self.dictionaryEnd + self.reusable
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self.dictionary = [None] * self.dictionaryEnd + self.dictionary
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self.dictionaryEnd -= 1
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self.dictionary[self.dictionaryEnd] = proper
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prevCommon = min(len(previous), len(proper))
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for i in range(0, prevCommon):
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if previous[i] != proper[i]:
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prevCommon = i
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break
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previous = proper
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self.reusable[self.dictionaryEnd] = prevCommon
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#part = self.dictionary[self.dictionaryEnd : len(self.dictionary) - 1]
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#part.sort()
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#self.dictionary[self.dictionaryEnd : len(self.dictionary) - 1] = part
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#
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#index = len(self.dictionary) - 1
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#while index >= self.dictionaryEnd:
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# proper = self.dictionary[index]
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# prevCommon = min(len(previous), len(proper))
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# for i in range(0, prevCommon):
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# if previous[i] != proper[i]:
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# prevCommon = i
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# break
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# previous = proper
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# self.reusable[self.dictionaryEnd] = prevCommon
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# index -= 1;
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'''
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Finds the closests correct spelled word
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@param used:str The word to correct
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@return (words, distance):(list<string>, int) A list the closest spellings and the weighted distance
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'''
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def correct(self, used):
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if len(used) > 127:
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return ([used], 0)
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self.__correct(used)
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return (self.corrections, self.closestDistance)
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'''
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Finds the closests correct spelled word
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@param used:str The word to correct, it must satisfy all restrictions
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'''
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def __correct(self, used):
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self.closestDistance = 0x7FFFFFFF
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previous = self.dictionary[-1]
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prevLen = 0
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usedLen = len(used)
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proper = None
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prevCommon = 0
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d = len(self.dictionary) - 1
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while d > self.dictionaryEnd:
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d -= 1
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proper = self.dictionary[d]
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if abs(len(proper) - usedLen) <= self.closestDistance:
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if previous == self.dictionary[d + 1]:
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prevCommon = self.reusable[d];
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else:
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prevCommon = min(prevLen, len(proper))
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for i in range(0, prevCommon):
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if previous[i] != proper[i]:
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prevCommon = i
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break
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skip = min(prevLen, len(proper))
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i = prevCommon
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while i < skip:
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for u in range(0, usedLen):
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if (used[u] == previous[i]) or (used[u] == proper[i]):
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skip = i
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break
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i += 1
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common = min(skip, min(usedLen, len(proper)))
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for i in range(0, common):
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if used[i] != proper[i]:
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common = i
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break
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distance = self.__distance(proper, skip, len(proper), used, common, usedLen)
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if self.closestDistance > distance:
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self.closestDistance = distance
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self.corrections = [proper]
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elif self.closestDistance == distance:
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self.corrections.append(proper)
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previous = proper;
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if distance >= 0x7FFFFF00:
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prevLen = distance & 255
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else:
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prevLen = len(proper)
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'''
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Calculate the distance between a correct word and a incorrect word
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@param proper:str The correct word
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@param y0:int The offset for `proper`
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@param yn:int The length, before applying `y0`, of `proper`
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@param used:str The incorrect word
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@param x0:int The offset for `used`
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@param xn:int The length, before applying `x0`, of `used`
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@return :float The distance between the words
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'''
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def __distance(self, proper, y0, yn, used, x0, xn):
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my = self.M[y0]
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for y in range(y0, yn):
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best = 0x7FFFFFFF
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p = proper[y]
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myy = self.M[y + 1] # only one array bound check, and at most one + ☺
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x = x0
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while x < xn:
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change = my[x]
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u = used[x]
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if p == u:
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# commence black magick … twilight would be so disappointed
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x += 1
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myy[x] = change
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best = min(best, change)
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remove = myy[x]
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add = my[x + 1]
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cw = 1
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if my[x] in self.weights:
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if p in self.weights[u]:
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cw = self.weights[u][p]
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x += 1
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myy[x] = min(cw + change, 1 + min(remove, add))
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if best > myy[x]:
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best = myy[x]
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if best > self.closestDistance:
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return 0x7FFFFF00 | y
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my = myy
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return my[xn]
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