ponysay/src/spellocorrecter.py
Pablo Lezaeta f65be435ac Update copyright and copyleft year in the sourcecodes
Signed-off-by: Pablo Lezaeta <prflr88@gmail.com>
2016-05-31 00:53:02 -04:00

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#!/usr/bin/env python3
# -*- coding: utf-8 -*-
'''
ponysay - Ponysay, cowsay reimplementation for ponies
Copyright (C) 2012-2016 Erkin Batu Altunbaş et al.
This program is free software: you can redistribute it and/or modify
it under the terms of the GNU General Public License as published by
the Free Software Foundation, either version 3 of the License, or
(at your option) any later version.
This program is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
GNU General Public License for more details.
You should have received a copy of the GNU General Public License
along with this program. If not, see <http://www.gnu.org/licenses/>.
If you intend to redistribute ponysay or a fork of it commercially,
it contains aggregated images, some of which may not be commercially
redistribute, you would be required to remove those. To determine
whether or not you may commercially redistribute an image make use
that line FREE: yes, is included inside the image between two $$$
lines and the FREE is and upper case and directly followed by
the colon.
'''
from common import *
class SpelloCorrecter(): # Naïvely and quickly ported and adapted from optimised Java, may not be the nicest, or even fast, Python code
'''
Class used for correcting spellos and typos,
Note that this implementation will not find that correctly spelled word are correct faster than it corrects words.
It is also limited to words of size 0 to 127 (inclusive)
'''
def __init__(self, directories, ending = None):
'''
Constructor
@param directories:list<str> List of directories that contains the file names with the correct spelling
@param ending:str The file name ending of the correctly spelled file names, this is removed for the name
-- OR -- (emulated overloading [overloading is absent in Python])
@param directories:list<str> The file names with the correct spelling
'''
self.weights = {'k' : {'c' : 0.25, 'g' : 0.75, 'q' : 0.125},
'c' : {'k' : 0.25, 'g' : 0.75, 's' : 0.5, 'z' : 0.5, 'q' : 0.125},
's' : {'z' : 0.25, 'c' : 0.5},
'z' : {'s' : 0.25, 'c' : 0.5},
'g' : {'k' : 0.75, 'c' : 0.75, 'q' : 0.9},
'o' : {'u' : 0.5},
'u' : {'o' : 0.5, 'v' : 0.75, 'w' : 0.5},
'b' : {'v' : 0.75},
'v' : {'b' : 0.75, 'w' : 0.5, 'u' : 0.7},
'w' : {'v' : 0.5, 'u' : 0.5},
'q' : {'c' : 0.125, 'k' : 0.125, 'g' : 0.9}}
self.corrections = None
self.dictionary = [None] * 513
self.reusable = [0] * 512
self.dictionaryEnd = 512
self.closestDistance = 0
self.M = [None] * 128
for y in range(0, 128):
self.M[y] = [0] * 128
self.M[y][0] = y
m0 = self.M[0]
x = 127
while x > -1:
m0[x] = x
x -= 1
previous = ''
self.dictionary[-1] = previous;
if ending is not None:
for directory in directories:
files = os.listdir(directory)
files.sort()
for filename in files:
if (not endswith(filename, ending)) or (len(filename) - len(ending) > 127):
continue
proper = filename[:-len(ending)]
if self.dictionaryEnd == 0:
self.dictionaryEnd = len(self.dictionary)
self.reusable = [0] * self.dictionaryEnd + self.reusable
self.dictionary = [None] * self.dictionaryEnd + self.dictionary
self.dictionaryEnd -= 1
self.dictionary[self.dictionaryEnd] = proper
prevCommon = min(len(previous), len(proper))
for i in range(0, prevCommon):
if previous[i] != proper[i]:
prevCommon = i
break
previous = proper
self.reusable[self.dictionaryEnd] = prevCommon
else:
files = directories
files.sort()
for proper in files:
if len(proper) > 127:
continue
if self.dictionaryEnd == 0:
self.dictionaryEnd = len(self.dictionary)
self.reusable = [0] * self.dictionaryEnd + self.reusable
self.dictionary = [None] * self.dictionaryEnd + self.dictionary
self.dictionaryEnd -= 1
self.dictionary[self.dictionaryEnd] = proper
prevCommon = min(len(previous), len(proper))
for i in range(0, prevCommon):
if previous[i] != proper[i]:
prevCommon = i
break
previous = proper
self.reusable[self.dictionaryEnd] = prevCommon
#part = self.dictionary[self.dictionaryEnd : len(self.dictionary) - 1]
#part.sort()
#self.dictionary[self.dictionaryEnd : len(self.dictionary) - 1] = part
#
#index = len(self.dictionary) - 1
#while index >= self.dictionaryEnd:
# proper = self.dictionary[index]
# prevCommon = min(len(previous), len(proper))
# for i in range(0, prevCommon):
# if previous[i] != proper[i]:
# prevCommon = i
# break
# previous = proper
# self.reusable[self.dictionaryEnd] = prevCommon
# index -= 1;
def correct(self, used):
'''
Finds the closests correct spelled word
@param used:str The word to correct
@return (words, distance):(list<string>, int) A list the closest spellings and the weighted distance
'''
if len(used) > 127:
return ([used], 0)
self.__correct(used)
return (self.corrections, self.closestDistance)
def __correct(self, used):
'''
Finds the closests correct spelled word
@param used:str The word to correct, it must satisfy all restrictions
'''
self.closestDistance = 0x7FFFFFFF
previous = self.dictionary[-1]
prevLen = 0
usedLen = len(used)
proper = None
prevCommon = 0
d = len(self.dictionary) - 1
while d > self.dictionaryEnd:
d -= 1
proper = self.dictionary[d]
if abs(len(proper) - usedLen) <= self.closestDistance:
if previous == self.dictionary[d + 1]:
prevCommon = self.reusable[d];
else:
prevCommon = min(prevLen, len(proper))
for i in range(0, prevCommon):
if previous[i] != proper[i]:
prevCommon = i
break
skip = min(prevLen, len(proper))
i = prevCommon
while i < skip:
for u in range(0, usedLen):
if (used[u] == previous[i]) or (used[u] == proper[i]):
skip = i
break
i += 1
common = min(skip, min(usedLen, len(proper)))
for i in range(0, common):
if used[i] != proper[i]:
common = i
break
distance = self.__distance(proper, skip, len(proper), used, common, usedLen)
if self.closestDistance > distance:
self.closestDistance = distance
self.corrections = [proper]
elif self.closestDistance == distance:
self.corrections.append(proper)
previous = proper;
if distance >= 0x7FFFFF00:
prevLen = distance & 255
else:
prevLen = len(proper)
def __distance(self, proper, y0, yn, used, x0, xn):
'''
Calculate the distance between a correct word and a incorrect word
@param proper:str The correct word
@param y0:int The offset for `proper`
@param yn:int The length, before applying `y0`, of `proper`
@param used:str The incorrect word
@param x0:int The offset for `used`
@param xn:int The length, before applying `x0`, of `used`
@return :float The distance between the words
'''
my = self.M[y0]
for y in range(y0, yn):
best = 0x7FFFFFFF
p = proper[y]
myy = self.M[y + 1] # only one array bound check, and at most one + ☺
x = x0
while x < xn:
change = my[x]
u = used[x]
remove = myy[x]
add = my[x + 1]
cw = 0 if p == u else 1
if my[x] in self.weights:
if p in self.weights[u]:
cw = self.weights[u][p]
x += 1
myy[x] = min(cw + change, 1 + min(remove, add))
if best > myy[x]:
best = myy[x]
if best > self.closestDistance:
return 0x7FFFFF00 | y
my = myy
return my[xn]